PHP上传图片到数据库并显示

互联网 19-12-19

PHP上传图片到数据库并显示

1、创建数据表

CREATE TABLE ccs_image (   id int(4) unsigned NOT NULL auto_increment,   description varchar(250) default NULL,   bin_data longblob,   filename varchar(50) default NULL,   filesize varchar(50) default NULL,   filetype varchar(50) default NULL,   PRIMARY KEY (id) )engine=myisam DEFAULT charset=utf8

2、用于上传图片到服务器的页面 upimage.html

<!doctype html> <html> <head>     <meta charset="UTF-8">     <meta name="viewport"           content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">     <meta http-equiv="X-UA-Compatible" content="ie=edge">     <style type="text/css">         *{margin: 1%}     </style>     <title>Document</title> </head> <body> <form method="post" action="upimage.php" enctype="multipart/form-data">     描述:     <input type="text" name="form_description" size="40">     <input type="hidden" name="MAX_FILE_SIZE" value="1000000"> <br>     上传文件到数据库:     <input type="file" name="form_data" size="40"><br>     <input type="submit" name="submit" value="submit"> </form> </body> </html>

3、处理图片上传的php upimage.php

<?php if (isset($_POST['submit'])) {     $form_description = $_POST['form_description'];     $form_data_name = $_FILES['form_data']['name'];     $form_data_size = $_FILES['form_data']['size'];     $form_data_type = $_FILES['form_data']['type'];     $form_data = $_FILES['form_data']['tmp_name'];          $dsn = 'mysql:dbname=test;host=localhost';     $pdo = new PDO($dsn, 'root', 'root');     $data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));     //echo "mysqlPicture=".$data;          $result = $pdo->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype)                   VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");     if ($result) {         echo "图片已存储到数据库";     } else {         echo "请求失败,请重试";

注:图片是以二进制blob形式存进数据库的,像这样

4、显示图片的php getimage.php

<?php       $id =2;// $_GET['id']; 为简洁,直接将id写上了,正常应该是通过用户填入的id获取的     $dsn ='mysql:dbname=test;host=localhost';     $pdo = new PDO($dsn,'root','root');     $query = "select bin_data,filetype from ccs_image where id=2";     $result = $pdo->query($query);     $result = $result->fetchAll(2); //    var_dump($result);     $data = $result[0]['bin_data'];     $type = $result[0]['filetype'];     Header( "Content-type: $type");     echo $data;

5、到浏览器查看已经上传的图片,看是否可以显示