利用php实现读取excel中的图片

要实现读取excel中的图片，可以通过phpspreadsheet来实现。phpspreadsheet是一个纯php编写的库，并引入了命名空间、PSR规范等。

使用composer安装phpspreadsheet

composer require phpoffice/phpspreadsheet

https://github.com/PHPOffice/PhpSpreadsheet

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excel图片如下图：

项目实例：

use PhpOffice\PhpSpreadsheet\Cell\Coordinate; use PhpOffice\PhpSpreadsheet\IOFactory; $imageFilePath = './uploads/imgs/'; //图片本地存储的路径 if (!file_exists($imageFilePath)) { //如果目录不存在则递归创建  mkdir($imageFilePath, 0777, true); } try {  $inputFileName = './files/1.xlsx'; //包含图片的Excel文件  $objRead = IOFactory::createReader('Xlsx');  $objSpreadsheet = $objRead->load($inputFileName);  $objWorksheet = $objSpreadsheet->getSheet(0);  $data = $objWorksheet->toArray();  foreach ($objWorksheet->getDrawingCollection() as $drawing) {   list($startColumn, $startRow) = Coordinate::coordinateFromString($drawing->getCoordinates());   $imageFileName = $drawing->getCoordinates() . mt_rand(1000, 9999);   switch ($drawing->getExtension()) {    case 'jpg':    case 'jpeg':     $imageFileName .= '.jpg';     $source = imagecreatefromjpeg($drawing->getPath());     imagejpeg($source, $imageFilePath . $imageFileName);     break;    case 'gif':     $imageFileName .= '.gif';     $source = imagecreatefromgif($drawing->getPath());     imagegif($source, $imageFilePath . $imageFileName);     break;    case 'png':     $imageFileName .= '.png';     $source = imagecreatefrompng($drawing->getPath());     imagepng($source, $imageFilePath, $imageFileName);     break;   }   $startColumn = ABC2decimal($startColumn);   $data[$startRow-1][$startColumn] = $imageFilePath . $imageFileName;  }  dump($data);die(); } catch (\Exception $e) {  throw $e; } public function ABC2decimal($abc) {  $ten = 0;  $len = strlen($abc);  for($i=1;$i<=$len;$i++){   $char = substr($abc,0-$i,1);//反向获取单个字符   $int = ord($char);   $ten += ($int-65)*pow(26,$i-1);  }  return $ten; }

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